In an experiment the refractive index of glass was observed to be `1.45 , 1.56 , 1.54 , 1.44 , 1.54 , and 1.53`. Calculate
(a). Mean value of refractive index
(b). Mean absolute error
( c ) Fractional error
(d) Percentage error
(e) Express the result in terms of absolute error and percentage error

In an experiment refractive index of glass was observed to be 1.45, 1.56, 1.54, 1.44, 1.54 and 1.53. The mean absolute error in the experiement is

In an experiment refractive index of glass was observed to be 1.45, 1.56, 1.54, 1.44, 1.54 and 1.53. The mean absolute error in the experiement is

The diameter of a wire as measured by a Screw gauge was found to be 1.328, 1.330, 1.325, 1.326, 1.334 and 1.336 cm. Calculate (i) mean value of diameter (ii) absolute error in each measurement (iii) mean absolute error (iv) fractional error (v) percentage error. Also, express the result in term of absolute error and percentage error.

The diameter of a wire as measured by a Screw gauge was found to be 1.328, 1.330, 1.325, 1.326, 1.334 and 1.336 cm. Calculate (i) mean value of diameter (ii) absolute error in each measurement (iii) mean absolute error (iv) fractional error (v) percentage error. Also, express the result in term of absolute error and percentage error.

In an experiment, the values of refractive indices of glass were found to be 1.54, 1.53, 1.44, 1.54, 1.56 and 1.45 in successive measurements (i) mean value of refreactive index of glass (ii) mean absolute error (iii) relative error and (iv) percentage error are respectively.