Mean and standard deviation of 100 observations were found to be 40 and 10 respecitly .If at the time of calculation two observations were wrongly taken as 30 ans 70 in place of 3 and 27 respectively , then find the correct standard deviation.

Mean and standard deviation of 100 observations were found to be 40 and 10, respectively . If at the time of calculation two observation were wrongly taken as 30 and 70 in place of 3 and 27 respectively, find the correct standard deviation.

Mean and standard deviation of 100 observations were found to be 40 and 10 respectively. If at the time of calculation two observations were wrongly taken as 30 and 70 in place of 3 and 27 respectively. Find the correct standard deviation.

Mean and standard deviation of 100 observations were found to be 40 and 10 respectively. If at the time of calculation two observations were wrongly taken as 30 and 70 in place of 3 and 27 respectively. Find the correct standard deviation.

Mean and standard deviation of 100 observations were found to be 40 and 10 respectively.If at the time of calculation two observations were wrongly taken as 30 and 70 in place of 3 and 27 respectively.Find the correct standard deviation.

Mean and standard deviation of 100 observations were found to be 40 and 10 respectively.If at the time of calculation two observations were wrongly taken as 30 and 70 in place of 3 and 27 respectively.Find the correct standard deviation.

Mean and standard deviation of 100 observations of are found to be 40 and 10. If at the time of calculation two observations are wrongly taken as 30 and 70 instead of 3 and 27 respectively. Find the correct standard deviation.

Mean and standard deviation of 100 observations of are found to be 40 and 10. If at the time of calculation two observations are wrongly taken as 30 and 70 instead of 3 and 27 respectively.Find the correct standard deviation.

The mean and the standard deviation of a characteristic of 100 items were found to be 60 and 10 respectively. At the time of calculations, two items were wrongly take as 5 and 45 instead of 30 and 20. Calculate the corrected mean and corrected standard deviation.

Mean of 100 observations is found to be 40. If at the time of computation two items are wrongly taken as 30 and 27 instead of 3 and 72, find the correct mean.