The length, a rod of aluminium is 1.0 m and its area of cross-section is `5.0 cm^(2)`. Its one end is kept at `250^(@)C` and the at `50^(@)C`. How much heat will flow in the rod in 5.0 minutes . K for Al =`2.0xx10^(-1) k J s^(-1) m^(-1) .^(@)C^(-1)` and `J=4.18 cal^(-1)`

The length of a rod of aluminium is 1.0 m and its area of cross-section is 5.0cm^(2) , its one end is kept at 250^(@)C and the other end at 50^(@)C . How much heat will flow in the rod in 5.0 minutes ? K or Al= 2.0xx10^(-1)kJ//sm^(@)C . Mention the required conditions.

The temperature difference between the ends of a rod of aluminium of length 1.0 m and area of cross section 5.0" cm"^(2) is 200^(@)C . How much heat will flow through the rod in 5 minutes ? The coefficient of thermal conductivity of aluminium is 0.2" kJ s"^(-1)" m"^(-1)" "^(@)C^(-1) .

A steel rod of length 1 m and area of cross section 1 cm^(2) is heated from 0^(@)C to 200^(@)C without being allowed to extend or bend. Find the tension produced in the rod (Y=2.0 xx 10 ^(11) Nm ^(-1) , alpha = 10 ^(-5) ^(@)C ^(-1))

The heat is flowing through a rod of length 50 cm and area of cross-section 5cm^(2) . Its ends are respectively at 25^(@)C and 125^(@)C . The coefficient of thermal conductivity of the material of the rod is 0.092 kcal // m × s ×.^(@) C . The temperature gradient in the rod is

Heat is flowing through a rod of length 25.0 cm having cross-sectional area 8.80 cm^(2) . The coefficient of thermal conductivity for the material of the rod is K = 9.2 xx 10^(-2) kcal s^(-1) m^(-1) .^(@)C^(-1) . The Temperatures of the ends of the rod are 125^(@)C and 0^(@)C in the steady state. Calculate (i) temeprature gradient in the rod (ii) temperature of a point at a distance of 10.0 cm from the hot end and (iii) rate of flow of heat.

A rod of 1m length and area of cross-section 1cm^(2) is connected across two heat reservoirs at temperature 100^(@)C and 0^(@)C as shown. The heat flow per second through the rod in steady state will be [Thermal conductivity of material of rod =0.09kilocalm^(-1)s^(-1)('^(@)C) ]

Find the thermal resistance of an aluminium rod of length 0.20 m and area of cross section 1xx10^(-4)m^(2) . The heat current is along the length of the rod. [Thermal conductivity of aluminium =200Wm^(-1)K^(-1) ]

The opposite faces of a cubical block of iron of cross-section 4 xx 10^(-4) "m"^(2) are kept in contact with steam and melting ice. Calculating the amount of ice melted at the end of 5 minutes. Given K=0.2 cal cm ""^(-1) "s"^(-1)°"C"^(-1) .

A uniform steel rod of length 50 cm is insulated on its sides. There is a layer of water of thick ness 0.2 mm at each end of the rod. If the ends of the rod are exposed to ice at 0^(@)C , and steam at 100^(@)C, calculate the temperature gradient in the rod. Thermal conductivities of steel and water are 0.11calcm^(-1)s^(-1) ""^(@)C^(-1) and 1.5xx10^(-3)calcm^(-1)s^(-1) ""^(@)C^(-1)

One end of a metal rod of length 1.0 m and area of cross section 100 cm^(2) is maintained at . 100^(@)C . If the other end of the rod is maintained at 0^(@)C , the quantity of heat transmitted through the rod per minute is (Coefficient of thermal conductivity of material of rod = 100 W//m-K )