If the centroid and two vertices of a triangle are (4,-8),(-9,7),(1,4) then the area of the triangle (in sq.units ) is `a(b)/(c)` then `(a)/(83)=`

If the centroid and two vertices of a triangle are (4.-8),(-9,7),(1,4) respectively. Then the area of the triangle ( in sq.units) is

If the centroid and two vertices of a triangle are (4,-8),(-9,7),(1,4) and the area of the triangle (in sq.units) is "K" ,then (8)/(333)K is equal to

If the area of the triangle is 4sq units, then x is

In Fig.3, the area of triangle ABC( in sq.units ) is :

If the centroid of a triangle is (1,4) and two of its vertices are (4,-3) and (-9,7) , then the area of the triangle is 183 sq.units (b) (183)/(2) sq.units (c)366 sq.units (d) (183)/(4) sq. units

If two vertices of a triangle are (1,3) and (4,-1) e and the area of triangle is 5 sq.units,then the angle at the third vertex lies in:

if the vertices of a triangle are (1,-3)(4,p)(-9,7) and its are area 15 Squnits then find the value of P

The centroid of a triangle lies at the origin and the coordinates of its two vertices are (-8, 0) and (9, 11), the area of the triangle in sq. units is

If the vertices of a triangle are (1,-3),(4,p) and (-9,7) and its area is 15 sq.units,find the value(s) of p.

the vertex of triangle are A(1,4,7),B(2,6,3) and C(-2,5,8) then centroid