If `bar(a)=hat i+hat j+2hat k, bar(b)=hat i+2hat j+2hat k` and `|bar(c)_(1)|=1` ,then the maximum value of `[bar(a)timesbar(b) quad bar(b)timesbar(c) quad bar(c)timesbar(a)]` is

If bar(P)=hat i+hat j+hat k,bar(Q)=2hat i-hat j-hat k , then bar(P)-bar(Q) is

If bar(a)=3hat i-3hat j-4hat k, bar(b)=hat i+2hat j+hat k and bar(c)=3hat i-hat j-2hat k , then [bar(a) bar(b) bar(c)] =

If bar(a)=(3hat i-hat j)/(sqrt(10)),bar(b)=(hat i+3hat j+hat k)/(sqrt(11)), then the value of (2bar(a)+bar(b))*[(bar(a)timesbar(b))times(bar(a)-3bar(b))]

Let bar(a)=2hat i+hat j-2hat k,bar(b)=hat i+hat j and bar(c) be a vector such that |bar(c)-bar(a)|=3,|(bar(a)timesbar(b))timesbar(c)|=3 and the angle between bar(c) and bar(a)timesbar(b) is 30^(@) . Then, bar(a).bar(c) is equal to

If bar(a)=hat i+2hat j-hat k and bar(b)=3hat i+hat j-5hat k find a unit vector in a direction parallel to vector (bar(a)-bar(b))

Let bar(a)=3hat i+2hat j+2hat k , bar(b)=hat i+2hat j-2hat k .Then a unit vector perpendicular to both bar(a)-bar(b) and bar(a)+bar(b) is

If bar(a)=phat i+3hat j-7hat k, bar(b)=phat i-phat j+4hat k and if the angle between bar(a) and bar(b) is acute, then the values of p lies in.

If bar a=hat i+hat j-4hat k and bar(b)=hat 4i-hat j-2hat k then find (i) a unit vector in the direction of the vector (2bar(a)-bar(b))

Let bar(a)=3hat i+2hat j+2hat k,bar(b)=hat i+2hat j-2hat k Then a unit vector perpendicular to both bar(a)-bar(b) and bar(a)+bar(b) is

If bar(a)=2hat i-hat j+2hat k then the value of |bar(a)timeshat i|^(2)+|bar(a)timeshat j|^(2)+|bar(a)timeshat k|^(2)=