The image of the point (1,2,-1) on the plane containing the line `(x+1)/(-3)=(y-3)/(2)=(z+2)/(1)` and the point (0,7,-7) is

Which of the following points lie on the plane containing the line (x+1)/(-3)=(y-3)/(2)=(z+2)/(1) and the point (0,7, -7)?

The image of the point (3,2,1) in the plane 2x-y+3z=7 is

then image of the point (-1,3,4) in the plane x-2y=0

The image of the point (-1, 3, 4) in the plane x-2y=0 is

The coordinates of the foot of the perpendicular from the point (1,-2,1) on the plane containing the lines, (x +1)/(6) = ( y-1)/(7) = (z-3)/(8) and (x-1)/(3) = (y-2)/(5) = (z-3)/(7), is :

The coordinates of the foot of the perpendicular from the point (1,-2,1) on the plane containing the lines,(x+1)/(6)=(y-1)/(7)=(z-3)/(8) and (x-1)/(3)=(y-2)/(5)=(z-3)/(7) is

Let Q be the foot of the perpendicular from the point P(7, - 2, 13) on the plane containing the lines (x+1)/6=(y-1)/7=(z-3)/8 and (x-1)/3=(y-2)/5=(z-3)/7 . Then (PQ)^2 , is equal to ____