If `ax+13y+bz+c=0` is a plane through the line intersection of `2x+3y-z+1=0, x+y-2z+3=0` and is perpendicular to the plane `3x-y-2z=4`, then the value of `2a+3b+4c` is equal to

The equation of plane through the line of intersection of the planes 2x+3y+4z-7=0,x+y+z-1=0 and perpendicular to the plane x+y+z-1=0

The equation of a plane through the line of intersection of 2x+3y+z-1=0 and x+5y-2z+7=0 and parallel to the line y=0=z is

the equation of a plane through the line of intersection the planes x+2y=3,y-2z+1=0 and perpendicular to the first plane is:

Eqation of plane passing through line of intersection of planes x+y+z=1 and 2x+3y+z=5 and perpendicular to the plane x-y-z=0 is :

Find the equation of the plane through the line of intersection of the planes x+2y+3z+2=0 , 2x+3y-z+3=0 and perpendicular to the plane x+y+z=0

Find the equation of the plane passing through the intersection of the planes 2x+3y-z+1=0 and x+y-2z+3=0 and perpendicular to the plane 3x-y-2z-4=0

Plane passing through the intersection of the planes x+2y+z-1=0 and 2x+y+3z-2=0 and perpendicular to the plane x+y+z-1=0 and x+ ky+3z-1=0 .Then the value of k is

The plane x + 3y + 13 = 0 passes through the line of intersection of the planes 2x - 8y + 4z = p and 3x - 5y + 4z + 10 =0 . If the plane is perpendicular to the plane 3x - y - 2z - 4 = 0 , then the value of p is equal to

Find the equation of the plane passing through the line intersection of the plane: 2x-y=0 and 3z-y=0 and perpendicular to the plane 4x+5y-3z=8