If accelration of A is `2m//s^(2)` towards left and accleration of B is `1 m//s^(2)` towards left, then accleration of C is:

If acceleration of A is 2m//s^(2) to left and acceleration of B is 1m//s^(2) to left, then acceleration of C is-

In the figure acceleration of A is 1m//s^(2) upward, acceleration of B is 7m//s^(2) upward acceleration of C is 2m//s^(2) upward. The acceleration of D will be.

Block A is kept on block B as shown in figure. It is known that acceleration of block A is 2 m//s^(2) towards right and acceleration of block B is 3 m//s^(2) towards right under the effect of unknown forces. Direction of friction force acting on A by B (mu_(AB) = 0.3)

Wedge B is pulled by an acceleration 2g towards left. Find the acceleration of block A-

If the wedge A shown in figure-1.93, is moving toward left with acceleration 3 m/s^(2) , find the net acceleration of block B which is constrainedtoslide along the wedge surface. (theta=30^(@))

An object is given an initial velocity of 11m/s towards the north and a constant acceleration of 2m//s^(2) towards the south. What will be the distance covered by the object in the sixth second of its motion

A bead kept at the bottom of a wedge moves towards right with a velocity 2v on a frictionless surface. If the wedge moves towards left with a velocity v while accelerating towards right with an acceleration a as shown then the magnitude of acceleration of the bead is x units. Find x if v = 3 m/s a = a = 16 m/s2 R = 9 m ? 2v 기

Find the acceleration of Block C when A moving towards the right direction with acceleration = 3 m/sec and acceleration of block B with respect to A is 4 m/sec? in the left direction all surfaces are smooth.