The abscissa of two points A and B are the roots of the equation `x^(2)+2ax-b^(2)=0` and their ordinates are the roots of `y^(2)+2py-q^(2)=0` then the distance AB in terms of a,b,p,q is

The abscissae of two points Aand B are the roots of the equation x^(2)+2ax-b^(2)=0 and their ordinates are the roots of y^(2)+2py-q^(2)=0 then the distance AB in terms of a,b,p,q is

The abscissa of the two points A and B are the roots of the equation x^(2)+2ax-b^(2)=0 and their ordinates are the roots of the equation x^(2)+2px-q^(2)=0. Find the equation of the circle with AB as diameter.Also,find its radius.

The abscisae of A and B are the roots of the equation x ^(2) + 2ax -b ^(2) =0 and their ordinates are the roots of the equation y ^(2) + 2 py -q ^(2) =0. The equation of the circle with AB as diameter is

The abscissae of two points A and B are the roots of the equaiton x^2 + 2x-a^2 =0 and the ordinats are the roots of the equaiton y^2 + 4y-b^2 =0 . Find the equation of the circle with AB as its diameter. Also find the coordinates of the centre and the length of the radius of the circle.

A abscissa of A and B are the roots of the equation x^2+2ax-b^2=0 and their ordinates are roots of the equation y^2+2py-q^2=0 . The equation of the circle with AB as diameter is

The abscissa of two points A and B are the roots of x^(2)-4x+2=0 and their ordinates are the roots of x^(2)+6x-3=0 .The equation of the circle with AB as diameter is

The abscissa of two A and B are the roots of the equation x ^(2) - 4x - 6=0 and their ordinates are the roots of x ^(2) + 5x - 4=0. If r is the radius of circle with AB as diameter, then r is equal to