" The potential energy of a body of mass "m" on the surface of earth is "

What is the potential energy of a body of mass m relative of the surface of Earth of radius R , at a (a) height h = R above its surface (b) depth d = R below its surface.

If the potential energy of a body at a height h from the surface of the earth is (mgR)/(2) , then

If g is the acceleration due to gravity on the earth's surface the gain in the potential energy of an object of mass m raised from the surface of the earth to a height equal to the radius R to earth is (NmgR)/(2) Find the value of N .

If g is the acceleration due to gravity on earth's surface, the gain of the potential energy of an object of mass m raised from the surface of the earth to a height equal to the radius R of the earth is

If g is the acceleration due to gravity on the earth's surface, the gain in the potential energy of an object of mass m raised from the surface of the earth to a height equal to the radius R of the earth, is

If 'g' is the potential energy of an object of mass 'm' raised from the surface of the earth to a height equal to the radius 'R' of the earth is

If g is the acceleration due to gravity on the earth’s surface, the gain in the potential energy of an object of mass m raised from surface of the earth to a height equal to radius R of the earth is - [M = mass of earth]

Find the gravitational potential energy of a body of mass 200 kg on the earth's surface. ["M(earth)"=6xx10^(24)"kg, R (earth)"=6400km]