If the roots of the equation `(1)/(x+p)+(1)/(x+q)=(1)/(r)` are equal in magnitude and opposite in sign, then `(p+q+r)/(r)`

If the roots of the equation (1)/(x+p)+(1)/(x+q)=(1)/(r) are equal in magnitude and opposite in sign,then (A)p+q=r(B)p+q=2rC ) product of roots =-(1)/(2)(p^(2)+q^(2)) (D) sum of roots =1

If the roots of the equation (1)/(x+a) + (1)/(x+b) = (1)/(c) are equal in magnitude but opposite in sign, then their product, is

If the roots of the equation (1)/(x+a)+(1)/(x+b)=(1)/(c) are equal in magnitude but opposite in sign , then their prodcut is :

Let p, q and r be real numbers (p ne q,r ne 0), such that the roots of the equation 1/(x+p) + 1/(x+q) =1/r are equal in magnitude but opposite in sign, then the sum of squares of these roots is equal to.

If the roots of the equation 1/(x+p) + 1/(x+q) = 1/r are equal in magnitude but opposite in sign and its product is alpha

If two roots of the equation x^(3)-px^(2)+qx-r=0 are equal in magnitude but opposite in sign,then: