The value of K such that the line `(x-4)/(1)=(y-2)/(1)=(z-k)/(2)` lies in the plane `2x-4y+pz=7` is

Value of k such that the line (x-4)/1 = (y-2)/1 =(z-k)/2 lies in the plane 2x-4y+z=7 is

The value of k such that (x-4)/(1)=(y-2)/(1)=(z-k)/(2) lies in the plane 2x-4y+z=7 is (A) 7(B)-7(C) no real value (D) 4

If the line (x-4)/(1)=(y-2)/(1)=(z-k)/(2) lies exactly on the plane 2x-4y+z=7 , the value of k is

The line (x-3)/(1)=(y-2)/(2)=(z-k)/(2) lies completely in the plane 2x-2y+z=0 for k equals

The line (x-4)/(1) =(2y-4)/(2)=(k-z)/(-2) lies exaclty in the plane 2x-4y+z=7 find the value of k

If the line (x-1)/(2)=(y-3)/(a)=(z+1)/(3) lies in the plane bx+2y+3z-4=0 , then

The angle between the line (x)/(3)=(y)/(4)=(z)/(5) "and the plane " 2x+y-2z=7 is