If `a,x_(1),x_(2)` are in G.P with common ratio `r` and `b,y_(1),y_(2)` are in G.P with common ratio `s` where `s-r=2`, then the area of the triangle with vertices `(a,b),(x_(1),y_(1)),(x_(2),y_(2))` is

If a, x_(1),x_(2) are in G.P with common ratio r and b, y_(1),y_(1) are in G.P with common ratio s where s-r=2 , then the area of the triangle with vertices (a,b),(x_(1),y_(1)),(x_(2),y_(2)) is

If a, x_(1), x_(2) are in G.P. with common ration r, and b, y_(1), y_(2) are in G.P. with common ratio s where s-r=2 , then the area of the triangle with vertices (a, b), (x_(1), y_(1)) and (x_(2),y_(2)) is

The area of the triangle OAB with vertices O(0,0),A(x_(1),y_(1))B(x_(2),y_(2)) is

The area of the triangle OAB with vertices O(0,0),A(x_(1),y_(1))" and B(x_(2),y_(2)) is

The centroid of the triangle with vertices at A(x_(1),y_(1)),B(x_(2),y_(2)),c(x_(3),y_(3)) is

" The area of the triangle OAB with vertices "O(0,0),A(x_(1),y_(1))" and "B(x_(2),y_(2))" is "ul(sq)" units "

Write the formula for the area of the triangle having its vertices at (x_(1),y_(1)),(x_(2),y_(2)) and (x_(3),y_(3))

If a,b,c form an A.P.with common difference d(!=0) and x,y,z form a G.P with a common ratio r(!=1), then the area of the triangle with vertices: (a,x),(b,y) and (c,z) is independent of (i) a (ii) b (ii) x (iv) r

if a,b,c form an A.P with common difference d (ne 0) and x,y,z form a G.P with common ratio r(ne1) then prove that the area of the triangle with vertices (a,x),(b,y) and (c,z) is independent ofa