The equivalent weight of hypo in the reaction (M=M" .Wt) \(2Na_{2}S_{2}O_{3}+I_{2} \rightarrow 2NaI+Na_{2}S_{4}O_{6}\) is

Suppose molecular weight of \(As_{2}S_{3}\) is M and the equivalent weight of \(As_{2}S_{3}\) in the reaction \(As_{2}S_{3}+H^{+}+NO_{3}^{-}\rightarrow NO+H_{2}O+AsO_{4}^{3-}+SO_{4}^{2-}\) is \(\frac{M}{14\times p}\) .Then 'p'=

The equivalent weight fo Na_2S_2O_3 in the reaction 2Na_2S_2O_3 + I_2 rarr Na_2 S_4O_6 + 2 NaI will be .

The equivalent weight of Na_(2)S_(2)O_(3) ( Mol. wt = M ) in the reaction , 2Na_(2)S_(2)O_(3) + I_(2) rarr Na_(2) S_(4)O_(6) + 2NaI is-

The equiv. wt. of hypo in the reaction Na_(2) S_(2) O_(3) + Cl_(2) + H_(2) O rarr Na_(2) SO_(4) + H_(2) SO_(4) + HCl is -

The equiv. wt. of hypo in the reaction Na_(2) S_(2) O_(3) + Cl_(2) + H_(2) O rarr Na_(2) SO_(4) + H_(2) SO_(4) + HCl is -

The change in oxidation number of "S" ,in the reaction of \(I_{2}\) with \(Na_{2}S_{2}O_{3}\) is

Find the n factor of Na_(2) S_(2) O_(3) in the following reactions. Na_(2) S_(2) O_(3) + I_(2) rarr NaI + Na_(2) S_(4) O_(6)