What is the phase difference,at a given instant of time, between two particles "25m" apart, when the wave of y(x,t)=0.03sin pi(2t-0.01x)" Where y and x are in metres and 't' in seconds travels in a medium?

A wave travels in a medium according to the equation of displacement given by y(x, t)=0.03 sin pi (2 t-0.01 x) where y and x are in metres and t in seconds. The wavelength of the wave is

The wave described by y = 0.25 "sin"(10 pi x - 2pit) , where x and y are in metres and t in seconds , is a wave travelling along the:

The wave described by y = 0.25 sin ( 10 pix -2pi nt ) where x and y are in meters and t in seconds , is a wave travelling along the

The equation of a wave is given by y=a sin (100t-x/10) where x and y are in metre an t in second, the velocity of wave is

When a wave travels in a medium displacement of a particle is given by y(x,t) =0.03sin pi (2t-0.01x) where y and x are in metres and in seconds,The phase difference at a given instant of time between two paticles 25 m apart in the medium is

A wave is represented by the equation, y = 0.1 sin (60 t + 2x) , where x and y are in metres and t is in seconds. This represents a wave

The equation of a progressive wave is y=0.02sin2pi[(t)/(0.01)-(x)/(0.30)] here x and y are in metres and t is in seconds. The velocity of propagation of the wave is