What would be the angular speed of earth, so that bodies lying on equator may experience weightlessness ?
( g = `10m//s^(2)` and radius of earth = 6400 km)

Find the angular speed of earth so that a body lying at 30^(@) latitude may become weightless.

What should be the angular speed of earth in radian/second so that a body of 5 kg weights zero at the equator? [Take g = 10 m//s^2 and radius of earth = 6400 km]

The angular speed of earth is "rad s"^(-1) , so that the object on equator may appear weightless, is (radius of earth = 6400 km)

What is the time period of rotation of the earth around its axis so that the objects at the equator becomes weightless? ( g=9.8 m//s^2 , radius of the earth =6400km )

If weight of an object at pole is 196 N then weight at equator is [ g = 10 m/s^2 , radius of earth = 6400 Km]

Suppose the earth increases it speed of rotation. At what new time period will the weight of a body on the equator becomes zero ? (Take, g = 10 ms^(-2) and radius of earth R = 6400 km)

In order to make the weight of a 5kg body to zero at the equator. The angular speed of the earth would must be (take, g = 10m//s^(2) and radius of the earh, R = 6400 km)

What is the angular speed of rotation about its polar axis, so that the bodies on its equator would fell no weight? ( g=9.8 m//s^(2),R=6.4xx10^(6)m)

Suppose the earth increases its speed of rotation . At what new time period will the weightof a body on the equator becomes zero? Take g=10 m/s^2 and radius of the earth R=6400 km .