Consider a variable force `F=(3x+5)N` acting on a body and if it is displaced from `x=2m` to `x=4m`, calculate the work done by this force.

A force of 3x^(2)-2x+5 acts on a body of mass 5 kg and displaces it from x=0 to x=4 m. What is the work done by the force?

A position dependent force F=7-2x+3x^(2) acts on a small body of mass 2 kg and displaced it from x=0 to x=5m . Calculate the work done in joule.

A force of (4x^(2)+3x)N acts on a particle which displaces it from x=2m to x = 3m . The work done by the force is

Certain force acting on a 20 kg mass changes its velocity from 5m//s to 2m//s . calculate the work done by the force.

A force vecF=(3x^(2)+2x-7)N acts on a 2 kg body as a result of which the body gets displaced from x=0 to x=5m. The work done by the force will be –

(a) What happens to the work done when the displacement of a body is at right angles to the direction of force acting on it ? Explain your answer. (b) A force of 50 N acts on a body and moves it a distance of 4 m on a horizontal surface. Calculate the work done if the direction of force is at an angle of 60^(@) to the horizontal surface.

The variation of force acting on a body with the displacement of body is shown in figure. Calculate work done by the force in the interval (i) 0le x lem (ii) 2m le x le 4m