A source of sound vibrates according to the equation y=0.05cos "pi t". It sends out wave of velocity "1.5ms^(-1)" .The wavelength of the wave is?

The equation y=0.15 sin 5 x cos 3000 t , describes a stationary wave. The wavelength of the stationary wave is

The equation of a sound wave is y=0.0015sin(62.4x+316t) the wavelength of this wave is

The equation y = 0.15 sin 5x cos 300t represents a stationary wave. The wavelength of this stationary wave will be -

The equation of a progressive wave is y=8 sin [ pi ((t)/(10)-(x)/(4))+(pi)/(3)] . The wavelength of the wave is

If the wave equation y= 0.08 sin (2 pi)/(lambda) (200t-x) then the velocity of the wave will be

Two sources S_1 " and "S_2 separated 2.0 m, vibrate according to equation y_1= 0.03 sin pi t " and " y_2= 0.02 sin pi t " where "y_1, y_2 and t are in M.K.S unit. They send out waves of velocity 1.5 m/s. Calculate the amplitude of the resultant motion of the particle co-linear with S_1 " and "S_2 and located at a point to the left of S_1 .

Two sources S_1 " and "S_2 separated 2.0 m, vibrate according to equation y_1= 0.03 sin pi t " and " y_2= 0.02 sin pi t " where "y_1, y_2 and t are in M.K.S unit. They send out waves of velocity 1.5 m/s. Calculate the amplitude of the resultant motion of the particle co-linear with S_1 " and "S_2 and located at a point To the right of S_2 .

Two sources S_1 " and "S_2 separated 2.0 m, vibrate according to equation y_1= 0.03 sin pi t " and " y_2= 0.02 sin pi t " where "y_1, y_2 and t are in M.K.S unit. They send out waves of velocity 1.5 m/s. Calculate the amplitude of the resultant motion of the particle co-linear with S_1 " and "S_2 and located at a point In the middle of S_2 " and "S_2 .