If A(6,3),B(-3,5),C(4,-2) and P(a,b) then the ratio of the areas of the triangles PBC,ABC is
|a+b|:7
|a-b|:7
|a+b+2|:7
|a+b-2|:7

If A(6,3),B(-3,5),C(4,-2) and P(a,b) then the ratio of the areas of the triangles PBC,ABC is |a+b|=7 |a-b|=7 |a+b+2|=7 |a+b-2|=7

If the coordinate of the point A,B,C and P are A(6,-3),B(-3,5),C(4,-2) and P(alpha,beta) then the ratio of the areas of the triangle PBC and ABC is

The coordinates of A,B,C are (6,3),(-3,5) and (4,-2) respectively and P is any point (x,y). Show that the ratio of the areas of triangles PBC and ABC is |(x+y-2)/(7)|

The coordinates of A ,B ,C are (6,3),(-3,5),(4,-2) , respectively, and P is any point (x ,y) . Show that the ratio of the area of P B C to that of A B C is (|x+y-2|)/7dot

When (0,0) is shifted to (3,-3) then the points P(5,5),Q(-2,4) and R(7,-7) are changed as A,B,C and if the area of triangle ABC is k then (86)/(k) is

If (3)/(5)A=(7)/(2)B=(7)/(5)C then find the ratio between A, B and C

If 2A = 3B = 7C, then what is the ratio of A : B : C?

When (0,0) shifted to (3,-3) the co- ordinates of P,Q,R are (5,5),(-2,4) and (7,-7) in the new system are A,B,C then area of triangle ABC in sq units is

If (a+3b)*(7a-5b)=0 and (a-4b)*(7a-2b)=0 . Then, the angle between a and b is

In triangle ABC, If tan((A-B)/2)=3/11 and a/b=7/4 then the value of angle C is