In an a.c. Circuit the voltage applied is `E=E_(0) sin (omega)t`. The resulting current in the circuit is `I=I_(0)sin((omega)t-(pi/2))`. The power consumption in the circuit is given by

In an AC circuit the voltage applied is E = E_(0) sin omega t . The resulting current in the circuit is I = I_(0) sin (omega t - (pi)/(2)) . The power consumption in the circuit is given by

In an a.c. circuit, the votlage applied is E = E_0 sin omegat . The resultig current in the circuit is I = I_0 sin (omegat - pi//2) . The power consumption in the circuit will be

In A.C. circuit, when E = E_0 sin omegat supply applied, current is obtained in circuit I=I_0 sin (omegat-pi/2) , so power consumed is circuit will be ……

The equation of an alternating voltage is E = 220 sin (omega t + pi // 6) and the equation of the current in the circuit is I = 10 sin (omega t - pi // 6) . Then the impedance of the circuit is

The equation of an alternating voltage is E = 220 sin (omega t + pi // 6) and the equation of the current in the circuit is I = 10 sin (omega t - pi // 6) . Then the impedance of the circuit is