Find the minimum and maximum angle of deviation for a prism with angle `A = 60^(@)` and `mu = 1.5`

Find the value of angle of minimum deviation of a prism.[Given mu=sqrt2,A=60^@ ]

The angle of minimum deviation for a prism is 37^(@) .If the angle of prism is 60^(@) , find the refractive index of the material of the prism.

A prism of refractive index mu and angle of prism A is placed in the position of minimum angle of deviation. If minimum angle of deviation is also A, then in terms of refractive index

The angle of minimum deviation for a prism is 40^(@) and the angle of the prism is 60^(@) . The angle of incidence in this position will be

The angle of minimum deviation for a prism is 40^(@) and the angle of the prism is 60^(@) The angle of incidence in this position will be

The angle of minimum deviation for a prism is 40^(@) and the angle of the prism is 60^(@) . The angle of incidence in this position will be