A projectile is projected from the ground making an angle of `30^(@)` with the horizontal.Air exerts a drag which is proportional to the velocity of the projectile

A projectile is projected from the ground by making an angle of 60^@ with the horizontal. After 1 s projectile makes an angle of 30^@ with the horizontal . The maximum height attained by the projectile is (Take g=10 ms^-2)

A projectile is projected from the ground by making an angle of 60^@ with the horizontal. After 1 s projectile makes an angle of 30^@ with the horizontal . The maximum height attained by the projectile is (Take g=10 ms^-2)

A projectile is projected from horizontal with velocity (u) making an angle 45^(@) with the horizontal direction. Find the distance of the highest point of the projectile from its starting point.

A particle is projected from . the ground at an angle theta with the horizontal with an initial speed of ‘u’. Find the time after which velocity vector, of the projectile is perpendicular to the initial velocity

A projectile is projected with velocity u making an angle theta with the horizontal, the equation of the path of the projectile is given by

A projectile is projected with velocity u making angle theta with horizontal direction, find : horizontal range.

A projectile is projected with velocity u making angle theta with horizontal direction, find : time of flight.

A projectile is thrown with velocity u making an angle theta with the horizontal. Its time of flight on the horizontal ground is 4 second. The projectile is moving at angle of 45^(@) with the horizontal just one second after the projection. Hence the angle theta is (take g=10m//s^(2) )