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If ionising energy of H atom is 13.6 eV,...

If ionising energy of H atom is 13.6 eV, then the second ionising energy of He should be

A

27.2 eV

B

40.8 eV

C

54.4 eV

D

108.8 eV

Text Solution

Verified by Experts

The correct Answer is:
C
`E_H=(-13.6)/n^2 , (E_1)_H=-13.6 eV`
`(E_1)He^(+)=-13.6Z^2/n^2=-13.6xx2^2/1=-54.4` eV
The second I.E. =`E_oo-(E_1)_(He^+)`
`=0-(-54.4) eV=54.4 eV`
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