The electronic configuration (outermost ) of `Mn^(+2)` ion (atomic number of Mn=25) in its ground state is

Options

A. `3d^5 , 4s^0`
B. `3d^4, 4s^1`
C. `3d^3 , 4s^2`
D. `3d^2, 4s^2 4p^2`

Answer

A

Explanation

`._25Mn=[Ar]3d^5 4s^2 underset"+2 electrons"overset"-2 electrons"hArr Mn^(2+) =[Ar]3d^5 4s^0`