Which of the following set of quantum numbers is correct for the `19^"th"` electron of chromium

Options

A. `{:(n,l,m,s),(3,0,0,1//2):}`
B. `{:(n,l,m,s),(3,2,-2,1//2):}`
C. `{:(n,l,m,s),(4,0,0,1//2):}`
D. `{:(n,l,m,s),(4,1,-1,1//2):}`

Answer

C

Explanation

`19^"th"` electron of chromium is `4s^1` n=4, l=0, m=0 , `s=+1/2`