The total number of electrons present in all `s` orbitals, all the `p` orbitals, and all the `d` orbitals of cesium ion are, respectively,

Options

A. 8,26,10
B. 10,24,20
C. 8,22,24
D. 12,20,22

Answer

B

Explanation

`(Cs_55)=1s^2, 2s^2, 2p^6 , 3s^2, 3p^6 , 3d^10 , 4s^2 4p^6 , 4d^10, 5s^2 , 5p^6, 6s^1`
`Cs^(+)=1s^2, 2s^2, 2p^6, 3s^2, 3p^6,3d^10,4s^2, 4p^6,4d^10, 5s^2 , 5p^6`
Total no. of `e^-` in s-orbitals =10
Total no. of `e^-` in p-orbitals =24
Total no. of `e^-` in d-orbitals =20