Home
Class 11
CHEMISTRY
The value of Planck's constant is 6.63 x...

The value of Planck's constant is `6.63 xx 10^(-34)Js`. The velocity of light is `3.0 xx 10^(8)ms^(-1)`. Which value is closest to the wavelength in nanometers of a quantum of light with frequency `8xx10^(15)s^(-1)`?

A

`3xx10^7`

B

`2xx10^(-25)`

C

`5xx10^(-18)`

D

`4xx10^1`

Text Solution

Verified by Experts

The correct Answer is:
D
`lambda=c/v = (3xx10^8)/(8xx10^15)=3.75xx10^(-8)`
`=3.75xx10^(-8)xx10^9 "nm"=4xx10^1` nm.
Promotional Banner

Similar Questions

Explore conceptually related problems

The value of Planck's constant is 6.63 xx 10^(-34)Js . The speed of light is 3xx10^(17)nm s^(-1) . Which value is the closed to the wavelength in nanometers of a quantum of light with frequency 6 xx 10^(10)s^(-1) ?

The value of planok,s constant is 6.63xx10^(-34)Js the speed of light is 3xx10^(17) nm s^(-1) which value is closest to the wavelength in nanometer of a quantum of light with frequency of 6xx10^(15) S^(-1) ?

The value of Planck's constant is 6.63 xx 10^-34 Js . The velocity of light is 3 xx 10^8 m//sec . Which value is closest to the wavelength of quantum of light with frequency of 8 xx 10^15 sec^-1 ?

The value of Planck's constant is 6.63 xx 10^-34 Js . The speed of light is 3 xx 10^(17)nms^(-1) . Which value is closest to the wavelength of quantum of light with frequency of 6 xx 10^15 sec^-1 ?

The value of Planck's constant is 6.62618 xx 10^(-34)Js . The number of significant figures in it is