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If the nitrogen atom has electronic conf...

If the nitrogen atom has electronic configuration `1s^(7)`, it would have energy lower than that of the normal ground state configuration `1s^(2)2s^(2)2p^(3)` because the electrons would be closer to the nucleus. Yet `1s^(7)` is not observed because it violates

A

Heisenberg uncertainly principle

B

Hund's Rule

C

pauli's exclusion principle

D

Bohr postulate of stationary orbits

Text Solution

Verified by Experts

The correct Answer is:
C
As per Pauli Exclusion principle "no two electrons in the same atom can have all the four quantum numbers equal or an orbital cannot contain more than two electrons and it can accommodate two electrons only when their directions of spin are opposite ".
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