`4:3` gm of an alkane is burnt in sufficient oxygen. The `CO_2` formed reacts cmpletely with 300mL , 2N NaOH solution producing `Na_(2)CO_(3)`. The alkane should be :

Aluminium react with Na_(2)CO_(3) to form

A gaseous alkane is exploded with oxygen. The volume of O_2 for complete combination to CO_2 formed in the ratio (7)/(4) . The molecular of alkane is :

The molarity of a 0.2 N Na_(2)CO_(3) solution will be :

How many gram glucose should be burnt completely to produce sufficient CO_(2) which may convert 12 gm NaOH into Na_(2)CO_(3) ?

How many gram glucose should be burnt completely to produce sufficient CO_(2) which may convert 12 gm NaOH into Na_(2)CO_(3) ?

When SO_(2) is passed into an Na_(2)CO_(3) solution, it produces

Standardization of Acid Solution: Calculate the normality of a solution of H_(2)SO_(4) if 40.0 mL of the solution reacts completely with 0.364 gram of Na_(2)CO_(3) . Strategy: Refer to the balanced equation. We are given the mass of Na_(2)CO_(3) , so we convert grams of Na_(2)SO_(3) to equivalents of Na_(2)CO_(3) , then to equivalents of H_(2)SO_(4) , which let us calculate the normality of the H_(2)SO_(4) solution.

0.8 mole of a mixture of CO and CO_(2) requires exactly 40 g of NaOH in solution for complete conversion of all the CO_(2) into Na_(2)CO_(3) . How many more moles of NaOH would it require for conversion into Na_(2)CO_(3) . If the mixture is completely oxidised to CO_(2) ?

The molarity of a 0.2 N Na_(2) CO_(3) solution will be