Consider a parallelogram whose vertices are A (1, 2), B (4, y), C (x, 6) and D (3, 5) taken in order.
What is the value of `AC^(2)-BD^(2)` ?

Consider a parallelogram whose vertices are A (1, 2), B (4, y), C (x, 6) and D (3, 5) taken in order. What is the area of the parallelogram ?

Consider a parallelogram whose vertices are A (1, 2), B (4, y), C (x, 6) and D (3, 5) taken in order. What is the point of intersection of the diagonals ?

The vertices of a parallelogram in order are A(1,2), B(4, y), C(x, 6) and D(3,5). Then (x, y) is

The vertices of a parallelogram in order are A(1, 2), B(4, y), C(x, 6), D(3, 5), then (x, y) =

The vertices of a parallelogram in order are A(1,2), B (4,y), C (x,6) and D(3,5) . Then (x,y) is :

A parallelogram has vertices A (4,4,-1),B (5,6, -1),C (6,5,1) and D ( x,y,z) . Then the vertex D is

A parallelogram has vertices A (4,4,-1), B(5,6,-1), C(6,5,1) and D(x,y,z). Then the vertex D is

If A(2, 3), B(1, 4), C(0 - 2) and D (x, y) are the vertices of a parallelogram, then what is the value of (x, y) ?

Show that the points A(7, 3), B(6, 1), C(8, 2) and D(9, 4) taken in that order are vertices of a parallelogram.