The means and standard devation of the marks of `200` candidates in half early exam were found to be `40` and `15` respectively. The marks of the candidates exceeds their marks by `10` in final exam. The mean and standard deviation of the marks in final exam are respectively ?

For a group of 200 candidates the mean and standard deviation were found to be 40 and 15 repectively . Later on it was found that the score 43 was misread as 34. Find the correct mean and standard deviation.

Find out the standard deviation of the marks secured by 10 students:

The mean and standard deviation of a group of 200 candidates are 40 and 15 respectively. Later on it was found to that one observation 43 was incorrectly copied down as 34. find the correct mean and standard deviation.

For a group of 100 candidatges the mean and standard deviation of their marks were found to be 60 and 15 respectively. Later on it was found that the scores 45 and 72 were wrongly entered as 40 and 27. Find the correct means and standard deviation.

For a group of 100 students, the mean bar(x)_(1) and the standard deviation sigma_(1) of their marks were found to be 40 and 15 respectively. Later it was observed that the scores 40 and 50 were misread as 30 and 60 respectively. If the mean and the standard deviation with the corrected observations of the scores, are bar(x)_(2) and sigma_(2) respectively , then

For a group of 200 candidates, the mean and standard deviation of scores were found to be 40 and 15 respectively. Later on if was discovered that the scores of 43 and 35 were misread as 34 and 53 respectively. Find the correct mean and standard derivation corresponding to the correted figures.

Mean and standard deviation of 100 observations were found to be 40 and 10 respectively.If at the time of calculation two observations were wrongly taken as 30 and 70 in place of 3 and 27 respectively.Find the correct standard deviation.

Mean and standard deviation of 100 observations were found to be 40 and 10 respectively.If at the time of calculation two observations were wrongly taken as 30 and 70 in place of 3 and 27 respectively.Find the correct standard deviation.

Mean and standard deviation of 100 observations were found to be 40 and 10 respectively. If at the time of calculation two observations were wrongly taken as 30 and 70 in place of 3 and 27 respectively. Find the correct standard deviation.