[" 1.The ends of latusrectum of a parabola are "(-3,1)" and "(1,1)" then equation of parabola is "],[" 2) "],[=2y],[" 4) "(x-1)^(2)=2y]

The ends of latusrectum of a parabola are (-3,1) and (1,1) then one of the equation of parabola is:

The extremities of latusrectum of a parabola are (1,1) and (1,-1) . Then the equation of the parabola can be

The extremities of latusrectum of a parabola are (1,1) and (1,-1) . Then the equation of the parabola can be

The extremities of latus rectum of a parabola are (1,1) and (1,-1). Then the equation of the parabola can be (a)y^(2)=2x-1(b)y^(2)=1-2x(c)y^(2)=2x-3(d)y^(2)=2x-4

The extremities of latus rectum of a parabola are (1, 1) and (1,-1) . Then the equation of the parabola can be (a) y^2=2x-1 (b) y^2=1-2x (c) y^2=2x-3 (d) y^2=2x-4

The extremities of latus rectum of a parabola are (1, 1) and (1,-1) . Then the equation of the parabola can be (a) y^2=2x-1 (b) y^2=1-2x (c) y^2=2x-3 (d) y^2=2x-4

The extremities of latus rectum of a parabola are (1, 1) and (1,-1) . Then the equation of the parabola can be y^2=2x-1 (b) y^2=1-2x y^2=2x-3 (d) y^2=2x-4

The extremities of latus rectum of a parabola are (1, 1) and (1,-1) . Then the equation of the parabola can be (a) y^2=2x-1 (b) y^2=1-2x (c) y^2=2x-3 (d) y^2=2x-4

The ends of the latus rectum of the parabola (x-2)^(2)=-6(y+1) are