The differential equation for a freely vibrating particle is `(d^2 x)/(dt^2)+ alpha x=0`. The angular frequency of particle will be

The differential equation of a particle performing a S.H.M. is (d^(2)x)/(dt^(2))+ 64x=0 . The period of oscillation of the particle is

The equation of motion of a particle executing SHM is ((d^2 x)/(dt^2))+kx=0 . The time period of the particle will be :

The equation of motion of a particle executing SHM is 3(d^(2)x)/(dt^(2))=27x=0 , what will be the angular frequency of the SHM?

The differential equation of a particle undergoing SHM is given by a a(d^(2)"x")/(dt^(2))+b"x"=0 . The particle starts from the extreme position. The ratio of the maximum acceleration to the maximum velocity of the particle is –

Passage XI) The differential equation of a particle undergoing SHM is given by a(d^(2)x)/(dt^(2)) +bx = 0. The particle starts from the extreme position. The ratio of the maximum acceleration to the maximum velocity of the particle is

Passage XI) The differential equation of a particle undergoing SHM is given by a(d^(2)x)/(dt^(2)) +bx = 0. The particle starts from the extreme position. The ratio of the maximum acceleration to the maximum velocity of the particle is

The equation of a damped simple harmonic motion is m(d^2x)/(dt^2)+b(dx)/(dt)+kx=0 . Then the angular frequency of oscillation is