if `A=[[cosa,sina],[-sina,cosa]]` then find `A^(-1)`

if SinA = 4/5 then find (1-SinA)/(1+CosA)

If 3sinA +4cosA=4, " then find " 4sinA -3cosA .

Evaluate the following determinants Delta=|{:(0,sina,-cosa),(-sina,0,sinbeta),(cosa,-sinbeta,0):}|

If (2sinA)/(1+sinA+cosA)=k then (1+sinA-cosA)/(1+sinA)=

If (2sinA)/(1+sinA+cosA)=k then (1+sinA-cosA)/(1+sinA)=

Select and write the correct answer from the given alternatives in each of the following: (frac(1+sinA+cosA)(1+sinA-cosA))=

Prove that (1+cosA)/(sinA) + (sinA)/(1+cosA) = 2/(sin A)

Simplify : sinA[(sinA,-cosA),(cosA, sinA)]+cosA[(cosA,sinA),(-sinA, cosA)] .

If sinA+cosA=(3)/(5) , then find the value of sinA-cosA .