" The magnetic moment of "[Ni(Cl)_(4)]^(2-)" is "

The magnetic moment of [Ni(CO_4)] is

Transition metals and many of their compounds show paramagnetic behaviour where there are unpaired electron or electrons. The magnetic moment arises from the spin and orbital motions in ions or molecule. Magnetic moment of n unpaired electrons is given as mu=sqrt(n(n+2)) Bohr magneton Magnetic moment increases as the number of unpaired electrons increases. Q. Magnetic moment of [Ni(CN)_4]^(2-) is zero but that of [Ni(H_2O)_4]^(2+) is 2.83BM . is because of :

Transition metals and many of their compounds show paramagnetic behaviour where there are unpaired electron or electrons. The magnetic moment arises from the spin and orbital motions in ions or molecule. Magnetic moment of n unpaired electrons is given as mu=sqrt(n(n+2)) Bohr magneton Magnetic moment increases as the number of unpaired electrons increases. Q. Magnetic moment of [Ni(CN)_4]^(2-) is zero but that of [Ni(H_2O)_4]^(2+) is 2.83BM . is because of :

Explain the hybridisation, geometry and magnetic property of [Ni(Cl)_(4)]^(2-) .

The magnetic moment of Ni^(+2) is sqrtx,'x' is

Geometry, hybridisation and magnetic moment of the ions [Ni(CN)_(4)]^(2-),[MnBr_(4)]^(2-) and [FeF_(6)]^(3-) respectively are .

Geometry, hybridisation and magnetic moment of the ions [Ni(CN)_(4)]^(2-),[MnBr_(4)]^(2-) and [FeF_(6)]^(3-) respectively are .

Find the change in magnetic moment when [Ni(H_(2)O)_(6)]^(2+) is converted into [Ni(NH_(3))_(6)]^(2+)