Forces `F_(1) and F_(2)` act on a point mass in two mutually perpendicular directions. The resultant force on the point mass will be

Force 3N, 4N and 12 N act at a point in mutually perpendicular directions. The magnetitude of the resultant force is :-

Force 3N, 4N and 12 N act at a point in mutually perpendicular directions. The magnetitude of the resultant resultant force us :-

Force 3N, 4N and 12 N act at a point in mutually perpendicular directions. The magnetitude of the resultant resultant force us :-

Force 3N, 4N and 12 N act at a point in mutually perpendicular directions. The magnetitude of the resultant resultant force us :-

A body is under the action of two mutually perpendicular forces of 3 N and 4 N. The resultant force acting on the body is

A body is under the action of two mutually perpendicular forces of 3 N and 4 N. The resultant force acting on the body is

A body is under the action of two mutually perpendicular forces of 3 N and 4 N. The resultant force acting on the body is

When forces F_(1), F_(2), F_(3) are acting on a particle of mass m such that F, and Fy are mutually perpendicular, then the particle remains stationary. If the force F, is now removed then the acceleration of the particle is :