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If x^2+p x+q=0 is the quadratic equation...

If `x^2+p x+q=0` is the quadratic equation whose roots are `a-2a n d b-2` where `aa n db` are the roots of `x^2-3x+1=0,` then `p-1,q=5` b. `p=1,1=-5` c. `p=-1,q=1` d. `p=1,q=-1`

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If x^(2)+px+q=0 is the quadratic equation whose roots are a-2 and b-2 where a and b are the roots of x^(2)-3x+1=0, then p-1,q=5 b.p=1,1=-5 c.p=-1,q=1 d.p=1,q=-1

If p and q are the roots of the equation x^2-p x+q=0 , then p=1,\ q=-2 (b) b=0,\ q=1 (c) p=-2,\ q=0 (d) p=-2,\ q=1

The value of p and q(p!=0,q!=0) for which p,q are the roots of the equation x^(2)+px+q=0 are (a)p=1,q=-2(b)p=-1,q=-2(c)p=-1,q=2(d)p=1,q=2

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Find the value of p for which the quadratic equation (p+1)x^(2)+-6(p+1)x+3(p+q)=0,p!=-1 has equal roots.Hence,find the roots of the equation.

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Suppose that the quadratic equations 3x^(2)+px+1=0 and 2x^(2)+qx+1=0 have a common root then the value of 5pq-2p^(2)-3q^(2)=

If one common root of the equations 3x^(2)+px+2=0 and -3x^(2)+qx+2=0 is alpha and product of other roots of equations is -1, then (a)p=5,q=-1(b)p=-5,q=-1(c)q=1,p=-5 (d) q=1,p=5

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