1 mole of ethyne on complete combustion gives

Options

A. 2 moles of carbon monoxide half -mole of water
B. 4 moles of carbon dioxide and 1 mole of water
C. 2 moles of carbon dioxide and 1 mole of water
D. 2 moles of carbon dioxide and 2 moles water

Explanation

To determine the products of the complete combustion of 1 mole of ethyne (C2H2), we will follow these steps:

### Step 1: Write the combustion reaction
The general reaction for the complete combustion of a hydrocarbon is:
\[ \text{Hydrocarbon} + \text{O}_2 \rightarrow \text{CO}_2 + \text{H}_2\text{O} \]

For ethyne (C2H2), the reaction can be written as:
\[ \text{C}_2\text{H}_2 + \text{O}_2 \rightarrow \text{CO}_2 + \text{H}_2\text{O} \]
...