`Na_(2)CO_(3).10H_(2)O` on exposure to air loses some water of crystallization and the rest on heating . How do you account for the above phenomenon ?

Explanation

To understand the phenomenon of `Na₂CO₃.10H₂O` losing water of crystallization when exposed to air and upon heating, we can break down the explanation into clear steps:

### Step-by-Step Solution:

1. **Identify the Compound**:
The compound in question is sodium carbonate decahydrate, represented as `Na₂CO₃.10H₂O`. This indicates that each formula unit of sodium carbonate is associated with 10 molecules of water (water of crystallization).

2. **Exposure to Air**:
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