If `sintheta = (3)/(5)`, then find the value of `tantheta and sectheta`.

Explanation

Given, `sintheta = (3)/(5)`
Let AOB be the right traingle such that, `angleOAB=theta`. ,
Assume that OB = 3 and AB = 5 (see fig. 8.5).
Then, `OA= sqrt( AB^(2)-OB^(2))=sqrt(25-9)= 4`.
So, `tantheta = ("Side opposite to " theta)/("Side adjacement to " theta)=(OB)/(OA)=(3)/(4)` and ,
`sectheta = ("Hypotenuse")/("Side adjacement to " theta)=(AB)/(OA)=(5)/(4)`.