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(tan^(3)theta-1)/(tantheta-1)= ....

`(tan^(3)theta-1)/(tantheta-1)`= ________.

A

`sec^(2) theta+ tantheta`

B

`sec^(2)theta-tantheta`

C

0

D

`tantheta-sec^(2)theta`

Text Solution

Verified by Experts

The correct Answer is:
A

Use `a^(3)-b^(3)=(a-b)(a^(2)+ab+b^(2))`.
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