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(cosecA-sinA)(secA-cosA)(tanA+cotA) = ....

`(cosecA-sinA)(secA-cosA)(tanA+cotA)` = __________.

A

-1

B

2

C

0

D

1

Text Solution

Verified by Experts

The correct Answer is:
D
Replace `cosecA " by " (1)/(sinA)and secA " by " (1)/(cosA)`.
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