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The value of log sin0^(@)+log sin1^(@)+l...

The value of log `sin0^(@)+log sin1^(@)+log sin2^(@)+* * *+log sin 90^(@)`is ________.

A

0

B

1

C

-1

D

undefined

Text Solution

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The correct Answer is:
To find the value of \( \log \sin 0^\circ + \log \sin 1^\circ + \log \sin 2^\circ + \ldots + \log \sin 90^\circ \), we can follow these steps: ### Step 1: Use the property of logarithms We know that \( \log a + \log b = \log(ab) \). Therefore, we can combine the logarithmic terms: \[ \log \sin 0^\circ + \log \sin 1^\circ + \log \sin 2^\circ + \ldots + \log \sin 90^\circ = \log(\sin 0^\circ \cdot \sin 1^\circ \cdot \sin 2^\circ \cdots \sin 90^\circ) \] ### Step 2: Evaluate \( \sin 0^\circ \) We know that \( \sin 0^\circ = 0 \). Therefore, when we multiply \( \sin 0^\circ \) with any other terms, the product will be zero: \[ \sin 0^\circ \cdot \sin 1^\circ \cdot \sin 2^\circ \cdots \sin 90^\circ = 0 \] ### Step 3: Substitute back into the logarithm Now substituting back into our logarithmic expression, we have: \[ \log(0) \] ### Step 4: Determine the value of \( \log(0) \) The logarithm of zero is undefined. Therefore, we conclude that: \[ \log \sin 0^\circ + \log \sin 1^\circ + \log \sin 2^\circ + \ldots + \log \sin 90^\circ \text{ is undefined.} \] ### Final Answer The value of \( \log \sin 0^\circ + \log \sin 1^\circ + \log \sin 2^\circ + \ldots + \log \sin 90^\circ \) is **undefined**.

To find the value of \( \log \sin 0^\circ + \log \sin 1^\circ + \log \sin 2^\circ + \ldots + \log \sin 90^\circ \), we can follow these steps: ### Step 1: Use the property of logarithms We know that \( \log a + \log b = \log(ab) \). Therefore, we can combine the logarithmic terms: \[ \log \sin 0^\circ + \log \sin 1^\circ + \log \sin 2^\circ + \ldots + \log \sin 90^\circ = \log(\sin 0^\circ \cdot \sin 1^\circ \cdot \sin 2^\circ \cdots \sin 90^\circ) \] ...
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