6(ax+by)=3a+2b;6(bx-ay)=3b-2a

Solve the following system of equations by method of cross-multiplication: 6(ax+by)=3a+2b,quad 6(bx-ay)=3b-2a

ax+by=a-b;bx-ay=a+b

(ax+by)^(2)+(bx-ay)^(2)

ax+by=2; bx+ay=3

Solve: ax + by = a - b bx - ay = a + b

Fractorise: (ax + by) ^(2) + (bx - ay)^(2)

Find the value of x and y: ax +by =a-b bx-ay =a+b

ax+by=a+b bx+ay=b^2

ax+by=5 bx+ay=3

{:(ax + by = 1),(bx + ay = ((a + b)^(2))/(a^(2) + b^(2))-1):}