What is the value of the acceleration due to gravity at a height equal to half of the radius of the Earth? Can we use the formula `g_(h) = g_(0) (1-(2h)/(R))`? Explain
(`"take" g_(0) = 9.8 ms^(-2)`).

Explanation

(i) (1.) Consider the formula, `m_(g) = (GMm)/(R^(2))`
Take acceleration due to gravity on the surface the earth as `'g_(o)'` from equation (1).
(2.) Find the acceleration due to gravity `(g_(h))` at a height (h) equal to half of the radius of the Earth from equation (1).
Find the ratio of `g_(o) "and" g_(h)`
Take the value of `g_(o) "as" 9.8 m s^(-2)`.
Find the value of `'g_(h)'`
(ii) `4.36 m s^(-2)`