The length of a brass rod is 1.5 m. Its coefficient of linear expansion is `19xx10^(-6)K^(-1)` Find the increase in length of the rod if it is heated through `20^(@)C`.

Options

A. `3.6xx10^(-6) m`
B. `5.7xx10^(-6) m`
C. `5.7xx10^(-4) m`
D. `3.6xx10^(-4) m`

Answer

C

Explanation

Given length of the rod, l=1.5 m.
Coefficeint of linear expansion, `alpha=19xx10^(-6)K^(-1)`.
Increase in temperature, `Deltatheta=20^(@)C`
`therefore" Increase in length, "Delta l = l xx alpha xx Delta theta`
`=(1.5)xx(19xx10^(-6))xx(20)=5.7xx10^(-4)` m.