A copper calorimeter of mass 100 g contains 200 g of ice at `-10^(@)C`. The thermal energy is upplied to the calorimeter and its contents at the rate of 50 calories per second. What is temperature of the calorimeter and its contents after ten minutes.
(Given, the specific heat of ice `=0.5 cal g^(-1)""^(@)C^(-1)`, the specific heat of copper `=0.1 cal g^(-1)""^(@)C^(-1)`, and latent heat of fusion of ice `=80 cal g^(-1)`

Explanation

(i) Use `=mL and Q= ms Delta theta ` according to the situation.
Use principle of calorimetery. Total heat produced = (mass of the substance ) `xx` (calorific value of the substance).
(ii) `5.46 MJ kg^(-1)`