Bose took 100 kg of paraffin oil and supplied `4180xx10^(3)`J of heat energy to it. Because of this, the temperature of the oil was found to increase from 300 K to x. With this data, Bose found the value of x. Find his answer. [Assume that there is no loss of energy to the surroundings and take the specific heat of water as `4.18 J g^(-1)""^(@)C^(-1)`( and water equivalent of 100 kg paraffin oil = 50 kg)].

Explanation

`Delta theta =75^(@)C`
`m=200 g`
`s=1 cal g^(-1)^(@)C^(-1)`
`therefore Q=msDelta theta =(200 g) (1 cal g^(-1)^(@)C^(-1))(75^(@)C)`
`=15000 cal`
The heat supplied = (Heat supply rate ). (time) The heat utilized = (thermal efficiency)
(heat supplied)
`rArr" "1500 cal =(80)/(100)xx250 cal s^(-1) xxts`
`rArr" "t=75` seconds.