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The mass suspended from the stretched st...

The mass suspended from the stretched string of a sonometer is 4 kg and the linear mass density of string `4 xx 10^(-3) kg m^(-1)` . If the length of the vibrating string is 100 cm , arrange the following steps in a sequential order to find the frequency of the tuning fork used for the experiment .
(A) The fundamental frequency of the vibratinng string is , n = `(1)/(2l) sqrt((T)/(m))`.
(B) Get the value of length of the string (l) , and linear mass density (m) of the string from the data in the problem .
(C) Calculate the tension in the string using , T = mg .
(D) Substitute the appropriate values in `n = (1)/(2l) sqrt((T)/(m))` and find the value of 'n' .

A

BCAD

B

ABCD

C

DCBA

D

BADC

Text Solution

Verified by Experts

The correct Answer is:
A

Given , l = 100 cm
`m = 4 xx 10^(-3) kg m^(-1)` (b)
T = mg = `4 xx 9.8 = 39.2`N (c)
Consider , the fundamental frequency of the vibration string is n , = `(1)/(2l) sqrt((T)/(m))` (a)
Substitute the values of l , T and m in n = `(1)/(2l) sqrt((T)/(m))` and calculate the value of n and this frequency of tuning fork (d) .
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