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An object is placed at a distance of 10 ...

An object is placed at a distance of `10 cm` from a convex mirror of focal length `15 cm`. Find the position and nature of the image ?

Text Solution

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In the given problem,
Object distance, u =- 10 cm (By using Cartesian sign convention)
Focal length of a convex mirror , f = + 15 cm (By sign convention)
` 1/f = 1/u + 1/v`
` rArr 1/v = 1/f - 1/u`
` rArr 1/v = 1/15 - 1/(-10)`
` v = (150)/25 = 6` cm.
Positive sign indicates that image is virtual.
Magnification = ` (-v)/u = (-6)/(-10) = 0.6`
Since 'm' is positive and less than one, the image is erect and diminished .
An erect, virtual, and diminished image is formed at 6 cm from the pole, behind the mirror.
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